Question
A body moves with uniform acceleration and covers 80 m
in 4 s and 160 m in next 4 s. Find initial velocity.Solution
We know the body moves with uniform acceleration, and the distance covered in two time intervals is given: Distance covered in the first 4 seconds = 80 m Distance covered in the next 4 seconds = 160 m Let the initial velocity be u u and the acceleration be a Using the equation for uniformly accelerated motion: 
For the first 4 seconds (time = 4 s, distance = 80 m): 80=4u+8a(Equation 1) For the next 4 seconds (time = 8 s, distance = 160 m): The distance covered from 4 to 8 seconds can be written as: 
This simplifies to: 80=4u+8a(Equation 2) Now, comparing Equation 1 and Equation 2, we see that both are identical: 4u + 8a = 80 Therefore, u=20m/s
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