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    Question

    A battery of emf 12 V and internal resistance 4 ohm is

    connected to a resistor. If the current in the circuit is 0.6 A, what is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed?
    A 8.6 V Correct Answer Incorrect Answer
    B 3.6 V Correct Answer Incorrect Answer
    C 9.6 V Correct Answer Incorrect Answer
    D 5.6 V Correct Answer Incorrect Answer

    Solution

    Emf of the battery, E = 12V Internal resistance of the battery, r = 4 ohm Current = 0.6 A so, I = E/(R + r) R + r = E/I   = 12/0.6 = 20 ohm Therefore = 20 - 4 = 16 ohm Terminal voltage of resistor = V so, V = IR => 0.6 x 16 => 9.6 V

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