Question
An electric dipole when held at 30 ֯ with respect to a
uniform electric field of 103 N/c experience a torque of 12 × 10-26 Nm. Calculate dipole moment of the dipole?Solution
Given that: θ = 30֯ τ = 12 × 10-26 Nm E = 103 N/C Dipole moment P needs to be calculated. It is known that torque is given by τ = PE sin θ => P = τ/ E sin θ => P = (12 × 10-26)/( 103 × sin 30 °) = 24 × 10-29 Cm
564.932 + 849.029 – 425.08 = 612.095 + ?
44.87% of (39.85 × ?) – 1520.88 0.51 = 1400.8
?% of (128.31 ÷ 15.97 × 75.011) = 419.98
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.) 
 (799.81/64) ÷ (10/799.92) × (129.84/130) = ?
...- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.) 
 What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
A boat can travel 30 km upstream and 45 km downstream in 6 hours. Find the speed of the boat in still water if the speed of the stream is 4 km/h.
? = 200.24 + 1077.97 – 14.992