Question
Two billiard balls each of mass 0.02 kg moving in
opposite directions with speed 5 m sβ1 collide and rebound with the same speed. What is the impulse imparted to each ball due to the other?Solution
Mass of each ball = 0.02 kg Initial velocity of each ball = 5 m/s The magnitude of the initial momentum of each ball, pi = mass Γ velocity = 0.02 Γ 5 = 0.1 kg m/s After the collision, the balls change their directions of motion without changing the magnitudes of their velocity. Final momentum of each ball, pf = β 0.1 kg m/s Impulse imparted to each ball = Change in the momentum of the system = pf β pi = β 0.1 β 0.1 = β 0.2 kg m/s The negative sign indicates that the impulses imparted to the balls are opposite in direction.
β1764 + 35 Γ 8 + 39 = ?2
18% of 200 - 16% of 150 = ?
25% of 30% of 3/5 of 14500 =?
2(1/3) + 2(5/6) β 1(1/2) = ? β 6(1/6)
7/3 of 4/5 of 15/56 of ? = 83
What will come in place of the question mark (?) in the following expression?
40% of 150 β ?% of 80 = 25% of 400
555.05 + 55.50 + 5.55 + 5 +0.55 = ?Β Β Β Β
64.5% of 800 + Β 36.4% of 1500 = (?)Β² + 38
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 Γ 4) = ?2Β
Simplify the following expression:
((32)4 - 1)/33Γ31Γ (210+1)