Question
Two long parallel conductors are placed 8mm apart from
each other carrying a current of 120 Amperes. What will be force per meter length of each one?Solution
We know the force per unit length between the two conductors is F/l = μ0I1I2/2πd Here d = distance = 8 × 10-3 meter μ = 4π × 10-7 F/m And currents I1 = I2 = 120 Ampere Therefore, F/l = (4π × 10-7 × 120 × 120)/(2π × 8 × 10-3) = 0.18 N/m
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