New RBI Grade B 2025 Notification will come Soon! Enroll Here

    Question

    Two long parallel conductors are placed 8mm apart from

    each other carrying a current of 120 Amperes. What will be force per meter length of each one?
    A 0.18 N/m Correct Answer Incorrect Answer
    B 0.08 N/m Correct Answer Incorrect Answer
    C 0.13 N/m Correct Answer Incorrect Answer
    D 0.20 N/m Correct Answer Incorrect Answer

    Solution

    We know the force per unit length between the two conductors is F/l = μ0I1I2/2πd Here d = distance = 8 × 10-3 meter μ  = 4π × 10-7 F/m And currents I1 = I2 = 120 Ampere Therefore, F/l = (4π × 10-7 × 120 × 120)/(2π × 8 × 10-3) = 0.18 N/m

    Practice Next

    Relevant for Exams: