Question
Two long parallel conductors are placed 8mm apart from
each other carrying a current of 120 Amperes. What will be force per meter length of each one?Solution
We know the force per unit length between the two conductors is F/l = μ0I1I2/2πd Here d = distance = 8 × 10-3 meter μ = 4π × 10-7 F/m And currents I1 = I2 = 120 Ampere Therefore, F/l = (4π × 10-7 × 120 × 120)/(2π × 8 × 10-3) = 0.18 N/m
If x + y + z = 4, xyz = 6 & x2 + y2 + z2 = 8 then find the value of x3 + y3 + z3.
If the ratio of the areas of two triangles is 4:3 and the ratio of their heights is 3:4, then the ratio of the lengths of their bases will be
(123×123×123 + 130×130×130)/(123×123 - 123×130 + 130×130) = ?
Find the value of
(1 - `1/(p+1)` ) + (1 - `2/(p+1)` ) + (1 - `3/(p+1)` ) + ........................... + (1 - `p/(p+1)` )
If x² + x = 11
find (x+4)³ +1/((x+4)³)
If x² + px + q = 0 has roots 4 and -3, find the values of p and q.
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If x = 19, then the value of x5 - 20x4 + 20x3 - 20x2 + 20x - 1 is
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