Question
A can do a certain work in 15 days and B can do
one-third of the same work in 10 days. A and B work together for 6 days and then A leaves. B completes the remaining work with C in 8 days. A and C together can complete the original work inSolution
B can do the work in = 30 days Let us suppose C can do the same work in x days. Now, A and B can do the part of work in 1 day is. Therefore, A and B can do the work together in 10 days, but they only did for 6 days. and the part of work done in 6 days is =6/10 th part of work. Now, The Remaining work = 1-10/ 6 =2/5 th part of work. Now, according to question B and C did the remaining work in 8 days Hence, in 1 day work done by B and C together is = 1/20th part of work Therefore, one day work of B and C together is =1/ 30 +1/x But it is given =1/ 20 as B and C does 2/5th part of work in 8 days
Given a triangle with two sides measuring 12 cm and 16 cm, which of the following cannot be a possible length for the third side?
- Find the remainder on dividing (5x 3  + 4x 2  – 10x + 1) by (2x – 4).
The area (in sq, units) of the triangle formed by the graphs of 8x + 3y = 24, 2x+8 = y and the x – axis is:
If x −y =4and xy =45,thenthevalueof x 3 −y3is:
If x + y = 2 and 1/x + 1/y = 18/15, then find the value of (x3 + y3)?
22% of ‘x’ is equal to 66% of ‘y’, then find the value of x: y.
If y + 1/y = 2 then find y117 + 1/(y117)
if a2 + b2 + c2Â =Â 2(4a -5b -9c)-122 , then a-b-c = ?
If a – b – c = 0, then the value of (a2 + b2 + c2)/(b + ac) is:
If 5x - 13xy + 6y = 0, find x : y.