Question
A bus moving on a straight road at a speed of 10 km/h
increases its speed to 70 km/h in 2 minutes. Find its average acceleration.Solution
To find the average acceleration of the bus, we'll use the formula for acceleration: Acceleration = Change in velocity/ Time taken The change in velocity is the final velocity minus the initial velocity. Given that the initial velocity (vi) is 10 km/h and the final velocity (vf) is 70 km/h, and the time taken is 2 minutes, we first need to convert the time to hours. 2 minutes = 2/60 hours = 1/30 hours Now, we can calculate the change in velocity: Change in velocity = uf- vi = 70 km/h -10 km/h = 60 km/h The time interval (At) over which this change occurs is 2 minutes. Since we typically use Sl units for such calculations (seconds or hours), and since the answers are in km/minute², let's keep the time in minutes for consistency. Thus, At = 2 minutes. Now, we calculate the average acceleration: a=60 km/h 2 minutes =30 km/h per minute To convert this to more standard units, let's express it in terms of km/min²:
LCM of two prime numbers 'p' and 'q' is 323 where p < q. Find the value of 'q'.
The greatest number of four digits which when divided by 5, 7, 9 leave remainders 3, 5, 7 respectively is:
The LCM of two numbers is 4 times of their HCF. The sum of LCM and HCF is 350. If one of the number is 200, then the other number is:
The H.C.F. of two numbers is 14 and the other two factors of their L.C.M. are 5 and 11. The larger of the two numbers is:
What is the highest common factor of 120 and 1800?
If the product of two numbers is 80 and their HCF is 5, then find the LCM of the given two numbers.
The HCF and the LCM of two numbers are 5 and 175, respectively. If the ratio of the two numbers is 5:7, the larger of the two numbers is _______.
If 'x' is the highest common factor (HCF) of 288 and 272, what is the product of the digits of 'x'?
Find the range of the given data:
99, 101, 85, 90, 112, 87, 95
The HCF of two numbers is 18. Which of the following can never be their LCM?