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    Question

    Oxidation number of Mn in KMnO₄

    is
    A -7 Correct Answer Incorrect Answer
    B +7 Correct Answer Incorrect Answer
    C -6 Correct Answer Incorrect Answer
    D +6 Correct Answer Incorrect Answer

    Solution

    In KMnO₄ (Potassium Permanganate),  K = +1 O = -2 (each oxygen) Let x be the oxidation number of Mn: (+1)+(x)+4(−2)=0(+1) + (x) + 4(-2) = 0 (+1)+(x)+4(−2)=01+x−8=01 + x - 8 = 0 1+x−8=0x=+7x = +7 x = +7 Hence, the oxidation state of Mn in KMnO₄ is +7.

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