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Let the price of items ‘A’, ‘B’ and ‘C’ be Rs. ‘p’, Rs. ‘q’ and Rs. ‘r’, respectively. Total price of items ‘A’ and ‘B’ = 960 × 2 = Rs. 1,920 Or, (p + q) = 1920 So, q = 1920 – p -------- (I) Total price of items ‘B’ and ‘C’ = 1020 × 2 = Rs. 2,040 Or, (q + r) = 2040 -------- (II) On putting value of ‘q’ from equation (I) in equation (II), we have; 1920 – p + r = 2040 Or, r – p = 120 So, p = r – 120 -------- (III) Total price of ‘C’ and ‘A’ = 975 × 2 = Rs. 1,950 Or, r + p = 1950 On putting value of ‘p’ from equation (III), we have; r + r – 120 = 1950 Or, 2r = 2070 So, r = 1035 Therefore, price of items ‘r’ = Rs. 1,035 Alternate solution Let the price of article ‘A’, ‘B’ and ‘C’ be Rs. ‘p’, Rs. ‘q’ and Rs. ‘r’, respectively. p + q = 1920 q + r = 2040 r + p = 1950 So, 2(p + q + r) = 5910 Or, p + q + r = 2955 So, price of article ‘r’ = 2955 – 1920 = Rs. 1,035
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