A wire measuring 656 meters in length is equal to 8 times the perimeter of a rectangular field. Determine the area of the rectangular field, given that its length exceeds its breadth by 5 meters.

ATQ,

Let the length and breadth of the field be ‘L’ metres and ‘B’ metres, respectively. Perimeter of the field = (656/8) = 82 metres So, 2 × (L + B) = 82 Or, (L + B) = 41 ATQ; L = B + 5 So, B + 5 + B = 41 Or, 2B = 36 So, B = 18 So, breadth of the field = 18 metres And, length of the field = 18 + 5 = 23 metres So, area of the field = 23 × 18 = 414 mLet the length and breadth of the ield be ‘L’ metres and ‘B’ metres, respectively. Perimeter of the field = (656/8) = 82 metres So, 2 × (L + B) = 82 Or, (L + B) = 41 ATQ; L = B + 5 So, B + 5 + B = 41 Or, 2B = 36 So, B = 18 So, breadth of the field = 18 metres And, length of the field = 18 + 5 = 23 metres So, area of the field = 23 × 18 = 414 m²