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Start learning 50% faster. Sign in nowSince the scores are normally distributed, we can use the z-score formula to standardize the scores and find the percentage of students who scored between 60 and 90. First, we need to find the z-score for a score of 60 and a score of 90. The z-score formula is: z = (x - μ) / σ where x is the score, μ is the mean, and σ is the standard deviation. For x = 60, we have: z = (60 - 75) / 10 = -1.5 For x = 90, we have: z = (90 - 75) / 10 = 1.5 Now we can use a z-score table or a calculator to find the percentage of students who scored between -1.5 and 1.5 standard deviations from the mean. This percentage represents the percentage of students who scored between 60 and 90 on the exam. Using a z-score table, we find that the percentage of students who scored between -1.5 and 1.5 is approximately 86.6%. Therefore, about 86.6% of the students scored between 60 and 90 on the exam.
Statements:
All A are B
All B are C
Some C are D
Conclusion:
I. All B are A
II. Some D are A
Read the given statements and conclusions carefully. Assuming that the information given in the statements is true, even if it appears to be at varianc...
You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decid...
Statements: Some oils are petrol.
All diesels are oils.
Conclusions: I. All die...
Statements:
N < J; S = M; J ≥ S; P > M
Conclusions:
I. M ≤ J
II. S < P
III. N > S
Statement :
No mobiles is a charger.
Some chargers are not phones.
No phone is a bell.
Conclusion :
I. No mobile...
Statements:
All Bottles are Glasses.
All Glasses are Bowls.
Some Cups are Bowls.
Conclusions:
I. Some Cups are Glasse...
Statements: All phones are battery.
No battery is a network.
...
Statements : All tools are menus.
No status is a menu.
All titles are status.
Conclusions: All menus being tools is a possi...
