Question
A group of 50 students took a test, and their scores
were normally distributed with a mean of 75 and a standard deviation of 10. What is the minimum score needed to be in the top 10% of the class?Solution
To be in the top 10% of the class, a student's score must be higher than 90% of the other scores. Using the standard normal distribution table, we can find that the z-score for the 90th percentile is 1.28. Using the z-score formula, we can find the minimum score needed to be in the top 10% of the class: x = mean + (z-score x standard deviation) = 75 + (1.28 x 10) = 87.8. Therefore, the minimum score needed to be in the top 10% of the class is 87.8.
Find the wrong number in the given number series.
68, 144, 304, 632, 1300, 2652
7, -26, -45, -60, -69, -73
72, 360, 370, 1850, 1880, 9300
Find the wrong number in the given number series,
9, 60, 299, 1199, 3599, 7199
3, 4, 9, 28, 116, 566, 3397
Find the wrong number in the given number series.
78, 103, 152, 233, 356, 523Find the wrong number in given number series.
1177, 1161, 1125, 1061, 961, 837.
Find the wrong number in the series.
3, 6, 18, 72, 360, 2160, 15120Find the wrong number in the given number series.
41, 51, 63, 80, 101, 126
- Find the wrong number in the given number series.
420, 369, 318, 277, 238, 225
Relevant for Exams:
