Question
A container is filled with 300 liters of hydrogen gas.
The first day it loses 100 liters of hydrogen gas and everyday it loses one-third of the volume it lost in the previous day. Then the containerSolution
First-day gas lost = 100 L Second day, gas lost = 100/3 = 33.33L Third day, gas lost = 33.33/3 = 11.11 L = 100/32 L Fourth day, gas lost = 11.11/3 = 3.7L = 100/33 L Fifth day, gas lost = 3.7/3 = 1.23L Sixth day, gas lost = 1.23/4 = 0.41L Seventh-day, gas lost = 0.41/3 = 0.137L Eighth day, gas lost = 0.137/3 = 0.045L Ninth day, gas lost = 0.045/3 = 0.015L Tenth day, gas lost = 0.015/3 = 0.005L Total gas loss is equal to 149.982L On 100Th day = 100/399 L Total lost in 100 day = 100 + 100/3 + 100/32 + .... + 100/399 = 100 [(1+ 1/3 + 1/32 + 1/33)/(1-(1/3))] = 150 [1 - (1/3100)] ∴ Possesses at least 150 litres of hydrogen gas on 100th day
(64/25)? × (125/512)?-1 = 5/8
(√529 + 63 /8)% of 800 = ?% of 250
(150% of 950) ÷ ? = 25
If 14 (x - y)Â = 2744 and 14 (x + y)Â = 537824, what is the value of x?
(106 + 14)/15 = ?/5
What will come in the place of question mark (?) in the given expression?
59.92 × 15.11 + √4224 = ? + 144.9Â
(125 × 12 × √8100) ÷ 150 = ?
- Calculate the value of this expression:
(180 - 90 ÷ 6 of 2) ÷ 5 + 3 of 16 ÷ 4 - 12 of 4 ÷ 8
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