Question
A alone can complete 50% of a work in 15 days while B
takes 10 days more than A to complete it. If B and C together can complete the work in 20 days, then find the time taken by C alone to complete the same work.Solution
Time taken by A alone to complete the entire work = 15/0.5 = 30 days Time taken by B alone to complete the entire work = 30 + 10 = 40 days Let the total work = L.C.M of 30, 40 and 20 = 120 units Then, efficiency of B = (120/40) = 3 units/day Combined efficiency of B and C = (120/20) = 6 units/day So, efficiency of C alone = 6 – 3 = 3 units/day So, time taken by C alone to complete the entire work = (120/3) = 40 days
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252 @ 28 @ 11 @ 5 @ 22 = 42
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32 * 8 * 55 * 42 * 7 * 305
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In the following question, select the related number from the given alternatives.
22 : 330 :: 28 : ?
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32 ÷ 5 X 184 - 8 + 78 Select the correct combination of mathematical signs to sequentially replace the * signs and to balance the given equation.
30 * 4 * 2 * 1 * 121
- Which two signs should be interchanged to correct the given equation?
5 + 3 × 8 – 12 ÷ 4 = 3 If '+' means '-', ' X ' means '+', '-' means '÷' and '÷' means ' X ', then what is the value of the following expression?
480 - 12 + 250 X 3...
If ‘P’ means ‘+’, V means ‘x’, T means ‘-‘ and ‘Q’ means “÷’ , then find ...
Select the different combination of mathematical signs that can sequentially replace the # sign and balance the given equation.
63 # 9 # 52 # 10 # 4 = 19
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