Question
A alone can complete 50% of a work in 15 days while B
takes 10 days more than A to complete it. If B and C together can complete the work in 20 days, then find the time taken by C alone to complete the same work.Solution
Time taken by A alone to complete the entire work = 15/0.5 = 30 days Time taken by B alone to complete the entire work = 30 + 10 = 40 days Let the total work = L.C.M of 30, 40 and 20 = 120 units Then, efficiency of B = (120/40) = 3 units/day Combined efficiency of B and C = (120/20) = 6 units/day So, efficiency of C alone = 6 – 3 = 3 units/day So, time taken by C alone to complete the entire work = (120/3) = 40 days
What Brand Strength Index (BSI) score did Amul achieve to be recognized as the world’s strongest food brand in 2024?
Who won the 2021 United States Grand Prix?
The approved ₹2000 crore grant to NCDC will enable it to raise how much from the open market?
Who won the Pulitzer Prize for Breaking News Photography in 2025 for capturing the assassination attempt on Donald Trump?
What is the currency of Laos?
Consider the following statements:
1. The auctions of the G-Secs are conducted on the electronic platform called the E-Kuber.
2. Only the ...
International literacy day is celebrated on which day ?
What is the main objective of the Varuna bilateral exercise between the Indian and French Navy?
Nua khai is celebrated in which of the following states?
What is the proposed financial assistance for Civil Services aspirants from Telangana who qualify for the Mains exams under the Rajiv Gandhi Civils Abha...