Question
The digits of a two-digit number βNβ are reversed to
form a new number βMβ. If M < N and N β M = 54, then which of the following maybe βNβ?Solution
ATQ; Let the original number = N = β10a + bβ So, the new number = M = β10b + aβ ATQ; N = M + 54 So, 10a + b = 10b β a + 54 Or, 9a β 9b = 54 Or, a β b = 6 So, possible pairs of βaβ and βbβ = (9, 3), (8, 2), (7, 1) So, possible values of βNβ = 93, 82, 71 Alternate Solution From option βaβ: N = 39 So, M = 93 Since, M > N {not possible} N = 71 So, M = 17 Also, N β M = 71 β 17 = 54
IfΒ (6000) 5Β = 7.776Β
If β35 = 5.9 find the value of
(161051)Β -3/5Β = ?
If β7 Γ β35 = xβ5, then find the value of x
If β30 = 5.5 find the value of
What will come in place of a?
169 1.7Β x Β 13 Β 2.5Β Β xΒ 169 1.5Β = 13 a
Simplify: (16)(3/4) Γ (8)(2/3)
Evaluate:
[1 / (3 + β5)] + [1 / (3 β β5)]
What will come in place of a?
(6)1.2 Γ (216 )2.7 Γ (36)2.7 = 6a
IfΒ (5000) 5Β = 3.125Β