Question
Which bank became the first public sector bank to extend
the facility of execution of on-line locker agreement through Digital Document Execution (DDE) Platform of National E-Governance Services Limited (NeSL)?Solution
Indian Bank became the first public sector bank to extend facility of execution of on-line locker agreement through Digital Document Execution (DDE) Platform of National E-Governance Services Limited (NeSL). On-line locker agreement, which is available round the clock will enhance customer convenience and will reduce the turn-around time of the agreement execution. DDE is a fully automated contract execution platform with paperless e-stamp and electronic signature (e-Sign) facility. The facility of e-Sign includes Aadhar based (OTP/Biometric) and dongle-based digital signature. The platform offers individual and multiple signatories to execute document in sequence, which will facilitate joint account holders also to execute on-locker agreement at their ease. Customers can track transaction status and download the Electronic Evidence (65B) certificate in real-time.The end to end digital process eliminates the need for physical stamp papers and signatures, making it faster and more efficient.
A right triangular pyramid XYZB is cut from cube as shown in figure. The side of cube is 16 cm. X. Y and Z are mid points of the edges of the cube. What...
What will be inradius of an equilateral triangle of side 4 cm?
In the given figure, radius of a circle is 14 √2 cm. PQRS is a square. EFGH, ABCD, WXYZ and LMNO are four identical squares. What is the total area (i...
In the figure P is a point which is 12 cm away from the centre of the circle O. A line drawn from P point cuts circle at point A and B respectively. If...
If in a ΔABC, AD is internal angle bisector & D is a point on BC, AB = 6cm, BC = 9cm then what is BD:CD?
The lengths of three medians in a triangles are 6 cm, 8 cm, 10 cm. What is the area of that traingle (in cm 2 )?
In the given figure. ‘O' is the centre of the circle and ∠BCA = 50°. The value of ∠BDA is:
In the figure given below, PQ is parallel to RS. What is