Start learning 50% faster. Sign in now
The Insurance Regulatory and Development Authority of India (IRDAI) has set up a 24-member committee to develop and suggest an affordable and comprehensive cover for the rural population. While the proposed cover will be a benefit based / parametric structure, called Bima Vistaar, the IRDAI has also asked the panel, which will be headed by Thomas M Devasia to recommend a regulatory framework for the cover. The insurance regulator has also asked the committee to develop and suggest constitution and operation of a preferably, women centric distribution channel to focus on reaching untapped/ rural areas – Bima Vahak – and recommend the regulatory framework. The committee will explore and recommend on how to bring about synergies in the working and operations of Bima Vahak, Bima Vistaar and the digital platform – Bima Sugam. According to IRDAI, in order to facilitate availability of an affordable, simple but comprehensive cover to the untapped areas and rural population, it is necessary to understand the needs and requirements in those areas and formulate suitable risk cover and customized distribution channels who appreciate the market dynamics in such areas.
What is the smallest number that is divisible by both 18 and 24 and is greater than 200?
What is the value of (2² + 3²) × (4³ + 5³) ÷ (6⁴)?
Find the remainder when 2722 is divided by 729.
18 is divided into three parts which are in arithmetic progression (A.P.) in such a way that the sum of their square is 158. Find the square of the sum
Find the remainder obtained by dividing 961125 by 37.
A number when divided by 45 leaves a remainder 21. What will be the remainder when the square of the same number is divided by 45?
If the 6-digit number 324a16 is completely divisible by 8, then the largest integer that can replace a is:
x + 5x – 2x – 24 has a zero at x = 6. Find the other zeros.
If a number 'a' is divisible by 18 and another number 'b' is divisible by 12, then (a2 – b2) is divisible by:
If ‘48b297a54’ is a nine digit number which is divisible by ‘11’, then find the smallest value of (a + b).