Question
Given that 3x-2y+297 = 0. SD(X) / SD(Y) = 4/3 Find r?
Solution
bxy = r { SD(X) / SD(Y)} Now, 3x = -297 + 2y X = -297/3 + 2/3 y bxy = 2/3 so, bxy = r { SD(X) / SD(Y)} 2/3 = r {4/3} r = ½ = 0.5
Question
bxy = r { SD(X) / SD(Y)} Now, 3x = -297 + 2y X = -297/3 + 2/3 y bxy = 2/3 so, bxy = r { SD(X) / SD(Y)} 2/3 = r {4/3} r = ½ = 0.5