Question
A dice was rolled 3 times. What is the probability of
getting 5 at least once?Solution
n = 3 p (success) = 1/6 q (failure) = 5/6 P (getting 5 at least once ) = 1 – P ( not getting 5) P (not getting 5 ) = 5/6 * 5/6 * 5/6 = 125 / 216 (3C0 p0 q3-0) P (getting 5 at least once ) = 1 – 125 / 216 = 91 / 216
More Research Questions
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
17% of 250 + ? = 108
32 + 26 × (484 ÷ 44) + 450 ÷ 9 = ?
40 × 5 + 27) × 9 = ?
What will come in the place of question mark (?) in the given expression?
193...
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
What will come in the place of question mark (?) in the given expression?
√1296 + (2/3 of 45% of 480) = ?
- Determine the value of ‘p’ if p = √529 + √1444
120% of 250 + 110 + 135 ÷ 5 = ?
