Question
The distribution of heights of American women aged 18 to
24 is approximately normally distributed with a mean of 65.5 inches and standard deviation of 2.5 inches. Calculate the z-score for a woman six feet tallSolution
Β Z = X-Mean / SD Β X= 6 feet = 6*12 inches = 72 inches Z = (72 β 65.5) / 2.5 = 2.6
32 × 3 (54 – 15) + 186 ÷ 3 ÷ 2 – (21)² = ?
17% of 250 + ? = 108
32 + 26 Γ (484 Γ· 44) + 450 Γ· 9 = ?Β
40 Γ 5 + 27) Γ 9 = ?
What will come in the place of question mark (?) in the given expression?
193...
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
What will come in the place of question mark (?) in the given expression?
β1296 + (2/3 of 45% of 480) = ?
- Determine the value of βpβ if p = β529 + β1444
120% of 250 + 110 + 135 Γ· 5 = ?