Question
If X and Y are independent random variables and
Var(X)=Var(Y)=4, then find Var(2X-3Y+1)?Solution
Var(2X-3Y+1) = (2)^2*VarX + (3)^2*Var(Y) + Var(1) = 4*4+ 9*4 = 16+36 = 52 Since, variance of constant is 0, so Var (1) is 0.
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