Question
 If f(x) is continuous for all real values of
x and f(x) takes on only rational values, then if f(1)=1, the value of f(0) isSolution
Property: - Let f:[0,1]→ R be continuous such that f(x)∈Q for any x∈[0,1] then f (x) is constant. Proof Suppose f isn't constant. Then for some a,b∈[0,1], f(a)≠f(b); Without Loss of Generality, f(a)
More Research Questions
Simplify the following expression:-
What will come in place of (?) in the given expression.
(14)² – (12)² = ?1.55 + 2.05 + 1.5 × 11 – 20% of 10.5 = ?
√ [? x 11 + (√ 1296)] = 16
(12 × 48 ÷ 6) ÷ 2 + ? = 106
172Â - 92Â + 121 - 74 = ?
125 + 64% of 250 = 150 + ?
(5/8 + 7/12) x 168 = ? + 93 - 25
Find the value of 16 X [(8 - 5) of 12 ÷ 4].
