Question
Suppose 6A = 8B = 15C, then find the value of (A:B:C)
.Solution
ATQ,
Let 6A = 8B = 15C = 'p'
So, 'A' = (p/6), 'B' = (p/8) and 'C' = (p/15)
Required ratio = (p/6) :(p/15) (p/8)
= (120/6) :(120/15) :(120/8) .........(LCM of 6, 8 and 15 is 120)
= 20:8:15
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