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Start learning 50% faster. Sign in nowATQ,
Let AB be the height of tower and AP be the shortest distance between points 'A' and 'P'.
In ΔABP,
sin 45° = (AB / AP)
(1/√2) = (60 / AP)
Or, AP = 60√2
Therefore, shortest distance between points 'A' and 'P' is 60√2 metres.
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