Question
Pipe 'X' alone takes 20 minutes to fill half of the empty
tank. Pipe 'Y' is twice as efficient as pipe 'X'. What percentage of the tank is filled by pipes 'X' and 'Y' working together in 10 minutes?Solution
ATQ,
Time taken by pipe 'X' alone to fill the entire tank = 20 × 2 = 40 minutes
Let the efficiency of pipe 'X' = 'x' units/minute
Then, total capacity of the tank = 40x units
Efficiency of pipe 'Y' = x × 2 = 2x units/minute
So, quantity of tank filled by pipes 'X' and 'Y' together in 10 minutes = (x + 2x) × 10 = 30x units
Percentage of tank filled = (30x / 40x) × 100 = 75%
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