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    Question

    Pipe 'X' alone takes 20 minutes to fill half of the empty

    tank. Pipe 'Y' is twice as efficient as pipe 'X'. What percentage of the tank is filled by pipes 'X' and 'Y' working together in 10 minutes?
    A 25% Correct Answer Incorrect Answer
    B 75% Correct Answer Incorrect Answer
    C 65% Correct Answer Incorrect Answer
    D 85% Correct Answer Incorrect Answer

    Solution

    ATQ,


    Time taken by pipe 'X' alone to fill the entire tank = 20 × 2 = 40 minutes

    Let the efficiency of pipe 'X' = 'x' units/minute

    Then, total capacity of the tank = 40x units

    Efficiency of pipe 'Y' = x × 2 = 2x units/minute

    So, quantity of tank filled by pipes 'X' and 'Y' together in 10 minutes = (x + 2x) × 10 = 30x units

    Percentage of tank filled = (30x / 40x) × 100 = 75%

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