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      Question

      Pipe 'X' alone takes 20 minutes to fill half of the empty

      tank. Pipe 'Y' is twice as efficient as pipe 'X'. What percentage of the tank is filled by pipes 'X' and 'Y' working together in 10 minutes?
      A 25% Correct Answer Incorrect Answer
      B 75% Correct Answer Incorrect Answer
      C 65% Correct Answer Incorrect Answer
      D 85% Correct Answer Incorrect Answer

      Solution

      ATQ,


      Time taken by pipe 'X' alone to fill the entire tank = 20 × 2 = 40 minutes

      Let the efficiency of pipe 'X' = 'x' units/minute

      Then, total capacity of the tank = 40x units

      Efficiency of pipe 'Y' = x × 2 = 2x units/minute

      So, quantity of tank filled by pipes 'X' and 'Y' together in 10 minutes = (x + 2x) × 10 = 30x units

      Percentage of tank filled = (30x / 40x) × 100 = 75%

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