Get Started with ixamBee
Start learning 50% faster. Sign in now
it is a very powerful test for testing the significance of the discrepancy between theory and experiment. It was given by Prof. Karl Pearson in 1900 and is known as the “chi-square test of goodness of fit”
Simplify the given expression.
(1/4) of {6 4 - 28 × 15 + 13 × 16 - 12.5 of 12 2 }
135÷ 15 x 19 + 14807 = ? + √3249 - √9604
3? x 23 ÷ √ 256 = 40.5
16 × ? + 36% of 250 = 410
√4761 ÷ 23 + √12769 = ? × 58
If 5√3+ √243 = 24.249, then what will be the value of √192+ 15√3.