Question
A stone of mass 16 kg is attached to a string 144 m long
and it is whirled in a horizontal circle. The maximum tension in the string can withstand is 16 N. The maximum velocity of revolution that can be given to the stone without breaking it, isSolution
For circular motion, Maximum tension = Centripetal force ∴ T = mv2/r Given, T= 16 N, m= 16 kg, r=144 m ∴ 16 = (16 x v2)/ 144 ⇒ v2 = 144 ⇒ v = 12 m/s
√1764 + 35 × 8 + 39 = ?2
18% of 200 - 16% of 150 = ?
25% of 30% of 3/5 of 14500 =?
2(1/3) + 2(5/6) – 1(1/2) = ? – 6(1/6)
7/3 of 4/5 of 15/56 of ? = 83
What will come in place of the question mark (?) in the following expression?
40% of 150 – ?% of 80 = 25% of 400
555.05 + 55.50 + 5.55 + 5 +0.55 = ?
64.5% of 800 + 36.4% of 1500 = (?)² + 38
What will come in the place of question mark (?) in the given expression?
25% of 1280 + (41 × 4) = ?2
Simplify the following expression:
((32)4 - 1)/33×31× (210+1)