What will be the percentage of porosity of a soil which has 1.5g/cm³ bulk density and 2.65 g/cm³ particle density?
Porosity (%) = [(Particle Density - Bulk Density) / Particle Density] x 100 Given: Bulk Density = 1.5 g/cm³ Particle Density = 2.65 g/cm³ Porosity (%) = [(2.65 - 1.5) / 2.65] x 100 Porosity (%) = (1.15 / 2.65) x 100 Porosity (%) = 0.434 x 100 Porosity (%) = 43.4%
Which is the largest six digit number, which when divided by 12, 15, 20, 24 and 30, leaves the remainders 8, 11, 16, 20 and 26 respectively.
If (a2 − b2)sin θ + 2ab cos θ = a2 + b2, then tan θ =
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