Amount of urea= N application rate kg/ha/N% in urea*100 =120/46*100= 260.87 kg/ha 260.87 kg urea is applied in 1 ha i.e. 10,000m2 area Therefore in 4000 m2, urea amount will be=260.87/10,000*4000= 104.38 kg
Consider the following statements with reference to the socio-economic conditions prevalent in India during the 18th century:
1. Agriculture ma...
Which policy is associated with Lord Wellesley, the Governor General of India from 1798 to 1805?
Where did Jawaharlal Nehru unfurl the Tricolour on August 5, 1947, during India's independence celebration?
Consider the following statements:
1. Lala Lajpat Rai played an instrumental role in the establishment of the Gurukul schools.
2. The S...
When was the All India Muslim League established during the era of British rule in India?
Consider the following statements:
1. The first revolutionary group in Bengal had started before the launch of the Swadeshi Programme.
...
Consider the following statements
1. The civil disobedience movement was the widespread participation of Women.
2. The formation of t...
Which Indian freedom fighter served in the British Army during the Anglo-Boer War in South Africa?
In the context of Indian history, what was the Dandi March
Who built the Tower of Victory (Vijay Stambha) in the Chittor Fort?
