Question
Caculate the amount of urea fr 4000 m2 area
if nitrogen appication rate is 120 kg/haSolution
Amount of urea= N application rate kg/ha/N% in urea*100 =120/46*100= 260.87 kg/ha 260.87 kg urea is applied in 1 ha i.e. 10,000m2 area Therefore in 4000 m2, urea amount will be=260.87/10,000*4000= 104.38 kg
A CC account shows frequent excess drawings, decline in stock levels, delays in statutory payments and high turnover in sister concerns. These indicator...
A term loan of ₹70 crore is classified as Doubtful. Realisable value of primary security is ₹40 crore and collateral security is ₹10 crore. The ba...
What is a Private Placement?
Consider the following and select which of them forms a part of capital receipts for the GoI
I.<...
A company shows Profit after Tax ₹14 crore, Depreciation ₹10 crore, Increase in Working Capital ₹6 crore and Term Loan repayment due next year ₹...
How many directors can be appointed by small shareholders in a company?
A doubtful asset (D1) has secured portion of ₹40 crore and unsecured portion of ₹20 crore. The secured portion has remained doubtful for less than o...
A company reported net profit before tax of Rs.36,100. It has raised debt capital of Rs.250,000 through 13% debentures. What is the interest coverage ra...
An NPA account has outstanding of ₹50 crore. The realisable value of security is estimated at ₹30 crore. The borrower offers a one‑time settlement...
As per Ind AS 7, dividend received is shown under:
Relevant for Exams:
